SOLVED: 'Why is 101 not in the sequence? Here are the first four terms of a number sequence 2. 10 18 14 (e) Write down the next term In the sequence 22 (
Consider a sequence of 101 term as (.^(100)C(0))/(1.2.3.4),(.^(100)C(1))/(2.3.4.5),(.^(100)C(2))/(3.4.5.6),.....(.^(100)C(100))/(101.102.103.104) If n^(th) term is greatest term of sequence, then n is equal to :- A)48 B)49 C)50 D)51
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If the sum of first 101 terms of an A. P. is 0 and If 1 be the first term of the A. P. then the sum of next 100 terms is
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Consider a sequence of 101 term as (.^(100)C(0))/(1.2.3.4),(.^(100)C(1))/(2.3.4.5),(.^(100)C(2))/(3.4.5.6),.....(.^(100)C(100))/(101.102.103.104) If n^(th) term is greatest term of sequence, then n is equal to :- A)48 B)49 C)50 D)51
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2-2+2-2+ .101\ \ t e r m s=?``-2` (b) 0 (c) 2 (d) None of these" - YouTube
SOLVED:The 20th term of an arithmetic sequence is 101, and the common difference is 3 . Find a formula for the nth term.
The sum of 101 terms of an A.P. is 1212 . The 51th term is
